Asked by Gabriel
A baseball is thrown upward from a height of 2m with an initial velocity of 10m/s. Determine its maximum height.
S(0) = 2m
S'(0) = 10m/s
S'(t) = -32t + 10
S(t) = -16t^2 + 10t + 2
I know that if you equal s(t) = 0 you get time, but how do I get maximum height?
Thanx in advanced!
S(0) = 2m
S'(0) = 10m/s
S'(t) = -32t + 10
S(t) = -16t^2 + 10t + 2
I know that if you equal s(t) = 0 you get time, but how do I get maximum height?
Thanx in advanced!
Answers
Answered by
Gabriel
answer is 7.1m ... i just don't know how to get there
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