Question

A baseball traveling upward passes a window 28.0 m above the street with a vertical speed of 13.0 m/s. If the ball was thrown from street level, what is the maximum height that the baseball reaches?

Answer 1

v = v i - g t
st top v = 0
so
t = vi/g to top
then
h = 28 + vi t - 4.9 t^2