Asked by Dylan
A helicopter traveling upward at 106 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?
I'm not sure what numbers to use. What formula to use or anything.. I think 106 m/s is the Vo^2 and 500 m is the h?
I had a similar question that was 120 m/s from 500 meters and got 15.8 seconds but the answer was 28.. Anyone have an idea of how to answer this?
I'm not sure what numbers to use. What formula to use or anything.. I think 106 m/s is the Vo^2 and 500 m is the h?
I had a similar question that was 120 m/s from 500 meters and got 15.8 seconds but the answer was 28.. Anyone have an idea of how to answer this?
Answers
Answered by
Henry
d = Vo*t + 05g*t^2 = 500 m.
-106*t + 4.9t^2 = 500
4.9t^2 -106t - 500 = 0
Use Quad. Formula and get
t = 26 s.
NOTE: The initial velocity is negative , because the helicopter is moving in opposite direction of package.
-106*t + 4.9t^2 = 500
4.9t^2 -106t - 500 = 0
Use Quad. Formula and get
t = 26 s.
NOTE: The initial velocity is negative , because the helicopter is moving in opposite direction of package.
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