d = Vo*t + 05g*t^2 = 500 m.
-106*t + 4.9t^2 = 500
4.9t^2 -106t - 500 = 0
Use Quad. Formula and get
t = 26 s.
NOTE: The initial velocity is negative , because the helicopter is moving in opposite direction of package.
A helicopter traveling upward at 106 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?
I'm not sure what numbers to use. What formula to use or anything.. I think 106 m/s is the Vo^2 and 500 m is the h?
I had a similar question that was 120 m/s from 500 meters and got 15.8 seconds but the answer was 28.. Anyone have an idea of how to answer this?
1 answer
1 answer