Asked by Dylan
A helicopter traveling upward at 120 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?
Answers
Answered by
Elena
I believe that there is mistake in your given data: the velocity has to be 12 m/s
There are two motions of the package:
1. upward motion with the initial velocity of 12 m/s
h=vₒ²/2g =144 /2•9.8 =7.34 m
H=500+7.34 =507.34 m
2. Dowmward motion (free fall)
t=sqrt(2H/g)=sqrt(2•507.34/9.8) =10.18 s.
If the speed is 120 m/s, calculate using your numbers.
There are two motions of the package:
1. upward motion with the initial velocity of 12 m/s
h=vₒ²/2g =144 /2•9.8 =7.34 m
H=500+7.34 =507.34 m
2. Dowmward motion (free fall)
t=sqrt(2H/g)=sqrt(2•507.34/9.8) =10.18 s.
If the speed is 120 m/s, calculate using your numbers.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.