Asked by joe
A helicopter 7.60 above the ground and descending at 3.90 drops a package from rest (relative to the helicopter). We have chosen the positive positive direction to be upward. The package falls freely.
A)Just as it hits the ground, find the velocity of the package relative to the helicopter.
vph=?m/s
B)Just as it hits the ground, find the velocity of the helicopter relative to the package
Vph=?m/s
A)Just as it hits the ground, find the velocity of the package relative to the helicopter.
vph=?m/s
B)Just as it hits the ground, find the velocity of the helicopter relative to the package
Vph=?m/s
Answers
Answered by
bobpursley
b. odd question. Is the helicopter desending at a constant rate of 3.9m/s? Helicopters do not ordinarily Fall under the influence of gravity.
a. Vf^2=Vi^2+2gh
Vf^2=3.9^2 + 2*9.8*7.6
relative to helicopter? subtract helicopter speed.
a. Vf^2=Vi^2+2gh
Vf^2=3.9^2 + 2*9.8*7.6
relative to helicopter? subtract helicopter speed.
Answered by
joe
for A is it 164.17
b. would be a upward direction
b. would be a upward direction
Answered by
joe
i didn't put 7.60m and 3.90m/s in the question problem
Answered by
joe
well i square rooted 164.17 and gave me 12.8128 then i put - 12.8 and it gave me a wrong anwser for my hw problem
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