Asked by Cope90
                A chemist needs 70 milliliters of a 40% solution, but only has 32% and 60% solutions available. How many millilitres of each should be mixed to get the desired solution?
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Answers
                    Answered by
            mathhelper
            
    amount of the 32% solution ---- x ml
amount of the 60% solution ----- 70-x ml
.32x + .6(70-x) = .4(70)
Now just solve for x
    
amount of the 60% solution ----- 70-x ml
.32x + .6(70-x) = .4(70)
Now just solve for x
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