Asked by Mary
How many milliliters of 0.201 M Ba(OH)2 solution are needed to completely neutralize 12.8 mL of 0.369 M HNO3 solution? The reaction is
Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H2O(l)
Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H2O(l)
Answers
Answered by
DrBob222
How many moles HNO3 do you have? That is M x L = moles HNO3.
Use the coefficients in the balanced equation to convert moles HNO3 to moles Ba(OH)2.
Then M Ba(OH)2 = moles Ba(OH)2/L Ba(OH)2. You know moles and M, solve for L and convert to mL.
Use the coefficients in the balanced equation to convert moles HNO3 to moles Ba(OH)2.
Then M Ba(OH)2 = moles Ba(OH)2/L Ba(OH)2. You know moles and M, solve for L and convert to mL.
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