Question
How many milliliters of O2 are consumed in the complete combustion of a sample of hexane, C6H14, if the reaction produces 325 mL of CO2? Assume all gas volumes are measured at the same temperature and pressure. The reaction is
2C6H14(g) + 19O2(g) -> 12CO2(g) + 14H2O(g)
2C6H14(g) + 19O2(g) -> 12CO2(g) + 14H2O(g)
Answers
When it's an all gas sample and the T and P don't change, you may use a shortcut and use volume directly as if they were mols.
2C6H14(g) + 19O2(g) -> 12CO2(g) + 14H2O(g)
325 mL CO2 x (19 mols O2/12 mols CO2) = 325 mL x (19/12) = mL O2 consumed.
2C6H14(g) + 19O2(g) -> 12CO2(g) + 14H2O(g)
325 mL CO2 x (19 mols O2/12 mols CO2) = 325 mL x (19/12) = mL O2 consumed.
Around 514.58?
Yes, and if your prof is picky about the number of significant figures you whould round that to 514 mL. You are limited to 3 from the 325 to start.
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