Asked by John
How many milliliters of 0.250 M KMnO4 are needed to react with 3.36 g of Iron(II) sulfate, FeSO4? The reaction is as follows:
10FeSO4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ¨ 5Fe2(SO4)3(aq) + 2MnSO4(aq) + K2SO4(aq) + 8 H2O(l
10FeSO4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ¨ 5Fe2(SO4)3(aq) + 2MnSO4(aq) + K2SO4(aq) + 8 H2O(l
Answers
Answered by
DrBob222
Follow the steps in this example. Post your work if you get stuck.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
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