Asked by Jesvlyn Garcia

Solve each problem algebraically using two variables.

The perimeter of a rectangle is 50 centimeters. The length is 9 centimeters more than the width. Find the length and the width of the rectangle
Answered by PsyDAG
L = W + 9

2L + 2W = 2(W+9) + 2W = 50

Solve for W, then L.
Answered by anonymous
P= 50
L= W + 9

P=2L + 2W
P= 2*(W +9) +2W
50 = 2W+18+2W
4W = 50-18
4W = 32
W = 8

L = W+9
L = 8 + 9
L = 17

therefore, L= 17 and w =8
not sure if my work is correct
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