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evaluate: integration of x^2 (square root of (1-2x^3))dx
16 years ago

Answers

drwls
Let u = 1-2x^3
du = =6 x^2 dx
Your integral is INTEGRAL u^1/2*(-du/6)
= -(1/6)*u^(3/2)/(3/2)
= -(1/9)(1-2x^3)^(3/2)

Check my math
16 years ago
joel
thanks
16 years ago

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