Asked by Adam
Integration
Given that:
t
∫ (3X + 2) dx = (13/2)
1
Find the value of t
Given that:
t
∫ (3X + 2) dx = (13/2)
1
Find the value of t
Answers
Answered by
Reiny
(3/2)x^2 + 2x | from 1 to t
= (3/2)t^2 + 2t - (3/2 + 2) = 13/2
(3/2)t^2 + 2t - 10 = 0
3t^2 + 4t - 20 = 0
(t - 2)(3t + 10) = 0
t = 2 or t = -10/3
depending on what interpretation is given to the integral, we might reject the t = -10/3
= (3/2)t^2 + 2t - (3/2 + 2) = 13/2
(3/2)t^2 + 2t - 10 = 0
3t^2 + 4t - 20 = 0
(t - 2)(3t + 10) = 0
t = 2 or t = -10/3
depending on what interpretation is given to the integral, we might reject the t = -10/3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.