Asked by mikey2
Use integration by parts to find
∫ 2x e-x dx.
∫ 2x e-x dx.
Answers
Answered by
Steve
u = 2x
du = 2dx
dv = e^-x dx
v = -e^-x
Now plug and chug
∫u dv = uv - ∫v du
du = 2dx
dv = e^-x dx
v = -e^-x
Now plug and chug
∫u dv = uv - ∫v du
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