Ask a New Question

Asked by Matthew

Find the equation of the tangent to the curve y = 2 - sqrt(x) perpendicular to the straight line y + 4x - 4 = 0. Can you guys help with finding the answer with steps?
4 years ago

Answers

Answered by oobleck
You want a line with slope 1/4
dy/dx = -1/(2√x)
so,
-1/(2√x) = 1/4
2√x = -4
Sorry. No such line. I suspect a typo.
4 years ago

Related Questions

Find the equation of the tangent and normal line of the equation: f(x) = √x^2 - 1, at x = 1 Show... find the equation of the tangent to the curve y=x^2-1/3x at x=2 Find the equation of the tangent to 3x^2 +4y^2 =7 at P(1, 1). (pls provide step by step, use impl... Find the equation of the tangent line to the graph of y=3^x−2 at x = 1. Give your answer in slope-in... Find the equation of the tangent line at the point on the graph of the equation y^2-xy-12=0, where x... Find the equation of the tangent to the following circles at the given coordinates: 1) x^2 +y^2 = 2... Find the equation of the tangent line for the curve x^2 + y^2 = 4 at the point (2, 0)
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use