Asked by Stefan
Find the equation of the tangent and normal line of the equation:
f(x) = √x^2 - 1, at x = 1
Show your complete solution
f(x) = √x^2 - 1, at x = 1
Show your complete solution
Answers
Answer
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Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
Assuming the usual carelessness with parentheses, We have
f(x) = √(x^2 - 1)
f'(x) = x/√(x^2 - 1)
so at (1,0),
the tangent is the line x=1
the normal line is the x-axis
Assuming the usual carelessness with parentheses, We have
f(x) = √(x^2 - 1)
f'(x) = x/√(x^2 - 1)
so at (1,0),
the tangent is the line x=1
the normal line is the x-axis
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