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Original Question
A body is projected upwards at any an angle of 30 degree with the horizontal and intial speed of 200 ms^1 in how many seconds W...Asked by Folake
A body is projected upward at an angle of 30 degree with the horizontal at an initial speed of 200ms-1 in how many seconds will it reach the ground?how far from the point of projection will it strike?
Answers
Answered by
R_scott
init horiz speed (h) ... 200 m/s * cos(30º)
init vert speed (v) ... 200 m/s * sin(30º)
flight time (t) ... 2 v / g
impact distance (d) ... h * t
init vert speed (v) ... 200 m/s * sin(30º)
flight time (t) ... 2 v / g
impact distance (d) ... h * t
Answered by
Felx
please answer this question and provide the diagram
Answered by
Abolua Raphael
Yes
Answered by
justine amos
Yes
Answered by
Zainab
Tita= 30°,U=200ms^-1
T=2Usintita/g
T=2(200)sin30/10
T=20secs.
T=2Usintita/g
T=2(200)sin30/10
T=20secs.
Answered by
EFE FAVOUR
I DONT UNDERSTAND
Answered by
Buzzy
You know nothing
Answered by
Favour
I want to be in this group
Answered by
Favour
What response
Answered by
Orose
For the first section,
Tita=30°
U=200ms^-1
g=10ms^-2
T=20seconds
As for the second one I don't get it
Tita=30°
U=200ms^-1
g=10ms^-2
T=20seconds
As for the second one I don't get it
Answered by
Toboy
For the first section
Tita =30 degree
U=200m/s
g=10m/s^-2
T=2Usintita/g
T=2*200Sin30/10
T=20sec then R=U^2Sin2tita/g
200^2Sin60/10
34641.016/10
Therefore R=3464.1m
Tita =30 degree
U=200m/s
g=10m/s^-2
T=2Usintita/g
T=2*200Sin30/10
T=20sec then R=U^2Sin2tita/g
200^2Sin60/10
34641.016/10
Therefore R=3464.1m
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