Question
A ball is projected upward at time t= 0.0s, from a point on the roof 10m above the ground. The ball rises, then falls until it strikes the ground. The initial velocity of the ball is 58.5 m/s. At time t=5.97s, what is the approximate velocity of the ball? Neglect air resistance.
Answers
drwls
Solve this equation using t = 5.97:
V = Vo - g t = 58.5 - 9.8 t
That will be zero, indicating that the ball is at its highest elevation.
V = Vo - g t = 58.5 - 9.8 t
That will be zero, indicating that the ball is at its highest elevation.
Renay
Why'd you use 9.8?
drwls
Because the acceleration of gravity (g) is 9.8 m/s^2.
Renay
Oh, okay, thanks.
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sk8er
how'd you get zero?