Asked by sam
an object is projected upward at a rate of 96 feet per second. find the time when it is 144 feet above the ground
Answers
Answered by
Reiny
h(t) = -16t^2 + 96t
144 = -16t^2 + 96t
t^2 - 6t + 9 = 0
(t-3)(t-3) = 0
t = 3
144 = -16t^2 + 96t
t^2 - 6t + 9 = 0
(t-3)(t-3) = 0
t = 3
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