Asked by roger
a stone is projected upward with a speed of 80.0ft/s from a 224 ft tower. find the maximum height and the speed at which it strikes the ground.
Answers
Answered by
MathMate
Assuming no air resistance, and PE at bottom of tower to be zero, then
At the maximum height,
mgh=(224mg+m(80²)/2
h=224+80²/(2g) [assume g=32.2 '/s²
=224'+99.38'
=323.38'
At bottom of tower,
mv²/2 = m(80²)/2+mg(224)
solve for v to get
v=144.31 '/s
At the maximum height,
mgh=(224mg+m(80²)/2
h=224+80²/(2g) [assume g=32.2 '/s²
=224'+99.38'
=323.38'
At bottom of tower,
mv²/2 = m(80²)/2+mg(224)
solve for v to get
v=144.31 '/s
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