Asked by lovelyn
A stone is projected upward at an angel of 30degree to the horizontal from the top of the tower of height 100m and it heat the ground at a point q,if the initial velocity of projection is 100m per second . calculate the following; maximum height of the stone above the ground, time it takes to reach the height ,time of flight , range covered
Answers
Answered by
oobleck
vertical distance is y = 100 + 100 sin30° t - 4.9t^2
horizontal distance is x = 100 cos30° t
so find the vertex of the parabola for max height and time to get there
then use that t to get the distance to q
horizontal distance is x = 100 cos30° t
so find the vertex of the parabola for max height and time to get there
then use that t to get the distance to q
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