Asked by Anonymous
Differentiate ( 4x+2)_3 with respect to x .hence,find the value of dy/ DX when x=1
Answers
Answered by
oobleck
I'll assume you meant
y = (4x+2)^3
If so, then by the chain rule,
dy/dx = 3(4x+2)^2 * 4
so, y'(1) = 3*6^2*4 = 288
y = (4x+2)^3
If so, then by the chain rule,
dy/dx = 3(4x+2)^2 * 4
so, y'(1) = 3*6^2*4 = 288
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