Asked by Anon
                Differentiate the following function from first principles
f(x)= 5x/(3-x)
            
            
        f(x)= 5x/(3-x)
Answers
                    Answered by
            oobleck
            
    just plug and chug
f(x+h) - f(x) = 5(x+h)/(3-x-h) - 5x/(3-x)
= (5(x+h)(3-x) - 5x(3-x-h)) / (3-x-h)(3-x)
= 15h / (3-x-h)(3-h)
Now divide by h and you have
15 / (3-x-h)(3-x)
Now take the limit as h->0 and you have
15/(3-x)^2
    
f(x+h) - f(x) = 5(x+h)/(3-x-h) - 5x/(3-x)
= (5(x+h)(3-x) - 5x(3-x-h)) / (3-x-h)(3-x)
= 15h / (3-x-h)(3-h)
Now divide by h and you have
15 / (3-x-h)(3-x)
Now take the limit as h->0 and you have
15/(3-x)^2
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