Question
What mass of Ca(OH)2 is required to prepare 200mL of 0.2N solution?
Answers
DrBob222
See your last post. M = 2 x N for Ca(OH)2.
Mols =M x L
g = mols x molar mass
Post your work if you get stuck.
Mols =M x L
g = mols x molar mass
Post your work if you get stuck.
Anonymous
I get 0.1 for Molarity.
N=Molarity*Equivalent
Equivalent=2 because you have two OH groups.
N=0.2
Molarity=0.1
0.2L*0.1M=moles
Moles*(molecular weight)=mass needed in grams
N=Molarity*Equivalent
Equivalent=2 because you have two OH groups.
N=0.2
Molarity=0.1
0.2L*0.1M=moles
Moles*(molecular weight)=mass needed in grams