Blessings

This page lists questions and answers that were posted by visitors named Blessings.

Questions

The following questions were asked by visitors named Blessings.

Mary is twice as old as Jane,the sum of squeres of their age is 125.How old is Jane?

What is chemic bonding?

ax^2+bx+c=0 solve by using completing the square.

The coordinats of C are (8,B) and dicoordinats ara (14,2) is CD=(6,-4) find thf value of B?

Education standard have gone down in our country,write a composition discribing what should be done inorder to lmprove education standard.

What is the past tenses and past perticiple of these word learn and sow?

Some one assist me to write application latter as hotel waiter.

Solve the quadratic equation using the quadratic formula, x^2-3x+2=0.

calculate the temperature of the gas when volume is 12m^3, if initially the volume was 8m^3 and its temperature was 30 °c.calculating by using charles laws.

Explain how you would prepare 250cm^3 of 0.2 m NaOH.

How to write a business plan?

A figure shows a uniform metre rule which is pivoted at the 20cm mark and balanced horizontally by an object of weight 3.15N placed at the 10cm mark. Calculate the weight of the metre rule.

An experiment in your laboratory requires exactly 500mL of 0.0200M solution of Na2CO3. You are given solid Na2CO3, distilled water and a 500mL volumetric flask. describe how you would prepare the required solution.

What mass of Ca(OH)2 is required to prepare 200mL of 0.2N solution?

If x =6, y = x +2 and z 1/2

√169/625 ÷22/5

An unknown compound is known to contain 30.34% M and 60.56% O. What is it's empirical formular

Answers

The following answers were posted by visitors named Blessings.

maybe it can be like this one 15x+y=0............(1) x+y=275........(2) solution x=275-y substitute x=275-y into equation 1 15(275-y)=0 4125-5y=0 5y=0+4125 5y=4125 dived 5 both sides y=275 substituting y=275 into equ 2 x+y=275 x+275=275 x=275-275 x=0 y=27...

I DONT KNOW BUT I DID C I tell if right it I got it right.

thank you I need food

I don't understand the question