Question
How much 0.200 M KOH is required to completely neutralize 25.0 mL of 0.150 M HClO4?
Answers
bobpursley
molesKOH=molesHClO4
volume*0.2=.025*.150
solve for volume in liters
volume*0.2=.025*.150
solve for volume in liters
18.75L
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