Asked by Madi
If you require 30.01 mL of 0.1798 M NaOH solution to titrate 10.0 mL of HC2H3O2 solution, what is the molar concentration of acetic acid in the vinegar?
Answers
Answered by
DrBob222
HC2H3O2 + NaOH ==> NaC2H3O2 + H2O
millimols NaOH = mL x M = 30.01 x 0.1798 = 5.396
millimols HC2H3O2 = the same since the ratio of base to acid is 1mol to 1 mol.
M HC2H3O2 = mmols/mL = 5.396/10.0 = ?
millimols NaOH = mL x M = 30.01 x 0.1798 = 5.396
millimols HC2H3O2 = the same since the ratio of base to acid is 1mol to 1 mol.
M HC2H3O2 = mmols/mL = 5.396/10.0 = ?
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