Ask a New Question

Asked by Madi

If you require 30.01 mL of 0.1798 M NaOH solution to titrate 10.0 mL of HC2H3O2 solution, what is the molar concentration of acetic acid in the vinegar?
5 years ago

Answers

Answered by DrBob222
HC2H3O2 + NaOH ==> NaC2H3O2 + H2O
millimols NaOH = mL x M = 30.01 x 0.1798 = 5.396
millimols HC2H3O2 = the same since the ratio of base to acid is 1mol to 1 mol.
M HC2H3O2 = mmols/mL = 5.396/10.0 = ?
5 years ago

Related Questions

We are doing a lab that requires finding the molarity of an unknown AgNO3 solution after reacting Na... If 5.00 mL of HCl require 4.59 mL of 0.9581 M NaOH to just consume the HCl, what is the concentratio... All of the following require breaking and forming chemical bonds except: freezing ice ** a p... If you require 29.40 mL of 0.529 M NaOH solution to titrate 194.2 mL of H2SO4 solution, what is the... This last one will require you enter an equation: p − 2 = 5 6 ( t − 5 ) d. How many mol SO, are required to make 118 mol CS? What does the US law require to happen after land is mined? Which of the following require citation? • A. Totally original content • B. Common knowledge • C.... Which of these is NOT a requirement to become a citizen for those immigrants who want to do so?... What would someone require to make their smart fridge send a shopping list to their laptop? (1 po...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use