Question
What mass (g) of KHP is required to neutralize 10.00 mL of 0.1092 M NaOH?
Answers
DrBob222
mols NaOH = M x L
mols NaOH = mols KHP
mols KHP = grams/molar mass. You know mols and molar mass, solve for grams.
mols NaOH = mols KHP
mols KHP = grams/molar mass. You know mols and molar mass, solve for grams.
Donnie
1.889g thanks Dr. Bob :)
DrBob222
I don't get 1.889 g KHP.
mol NaOH = 0.01 x 0.1092 =0.001092
mols KHP = 0.0001092.
mols KHP = grams KHP/molar mass KHP or
g KHP = mols KHP x molar mass KHP
= 0.0001092 x 204.22 = about 0.2230 g KHP.
mol NaOH = 0.01 x 0.1092 =0.001092
mols KHP = 0.0001092.
mols KHP = grams KHP/molar mass KHP or
g KHP = mols KHP x molar mass KHP
= 0.0001092 x 204.22 = about 0.2230 g KHP.