Asked by jen
An electric field does 14 J of work on a 0.0008 C charge.
What is the magnitude of the voltage change?
Answer in units of V.
The same electric field does 28 J of work on a 0.0016 C charge.
What is the magnitude of the voltage change now?
Answer in units of V.
What is the magnitude of the voltage change?
Answer in units of V.
The same electric field does 28 J of work on a 0.0016 C charge.
What is the magnitude of the voltage change now?
Answer in units of V.
Answers
Answered by
Damon
Force= electric field * charge F = E Q
work = energy change = F *d =E Q d
but E d = voltage change
so work = F * d = V Q
14 = V * 8*10^-4
V = (14/8)* 10^4
second one is twice the numerator and twice the denominator :)
work = energy change = F *d =E Q d
but E d = voltage change
so work = F * d = V Q
14 = V * 8*10^-4
V = (14/8)* 10^4
second one is twice the numerator and twice the denominator :)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.