Asked by jim
An electric field of 2.04 kV/m and a magnetic field of 0.548 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?
Answers
Answered by
drwls
Require that the magnetic and electrical forces be equal.
e*V*B = e*E
The charge, e, cancels out, so
V = (E/B)
If E is in V/m (NOT kV/m), and B is in Tesla, the answer will be in m/s.
V = 2040/0.548 = ?
e*V*B = e*E
The charge, e, cancels out, so
V = (E/B)
If E is in V/m (NOT kV/m), and B is in Tesla, the answer will be in m/s.
V = 2040/0.548 = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.