Question
An electric field of 2.04 kV/m and a magnetic field of 0.548 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?
Answers
drwls
Require that the magnetic and electrical forces be equal.
e*V*B = e*E
The charge, e, cancels out, so
V = (E/B)
If E is in V/m (NOT kV/m), and B is in Tesla, the answer will be in m/s.
V = 2040/0.548 = ?
e*V*B = e*E
The charge, e, cancels out, so
V = (E/B)
If E is in V/m (NOT kV/m), and B is in Tesla, the answer will be in m/s.
V = 2040/0.548 = ?