q= elementary charge = e = 1.602x10^-19C
F=qE
F=(1.6x10^-19C)(1.0x10^7N/C)
F=1.6x10^-12 N
F=qE
F=(1.6x10^-19C)(1.0x10^7N/C)
F=1.6x10^-12 N
Electric Force = Electric Field × Charge
Given:
Electric Field (E) = 1.0x10^7 N/C (directed into the cell)
Charge (q) = +e (charge on the sodium ion)
Substituting these values into the formula, we have:
Electric Force = (1.0x10^7 N/C) × (+e)
However, we need to convert the charge from elementary charge units to coulombs. The elementary charge (e) is approximately 1.6x10^(-19) coulombs.
So, the magnitude of the electric force on the sodium ion flowing into the cell can be calculated as:
Electric Force = (1.0x10^7 N/C) × (1.6x10^(-19) C)
Multiplying these values together, we get:
Electric Force = 1.6x10^(-12) N
Therefore, the magnitude of the electric force on the sodium ion flowing into the cell is 1.6x10^(-12) Newtons.
In this case, the electric field across the cellular membrane is given as 1.0x10^7 N/C directed into the cell, and the charge on the sodium ion is +e.
To get the magnitude of the electric force, we need to multiply the charge on the sodium ion by the electric field strength.
Given:
Electric field, E = 1.0x10^7 N/C
Charge on the sodium ion, q = +e
Now, we can substitute these values into the equation:
F = qE
F = (+e) * (1.0x10^7 N/C)
The numeric value of the elementary charge, e, is approximately 1.6 x 10^-19 C.
F = (1.6 x 10^-19 C) * (1.0x10^7 N/C)
Now, we can calculate the magnitude of the electric force:
F = 1.6 x 10^-19 C * 1.0x10^7 N/C
F = 1.6 x 10^-12 N
Therefore, the magnitude of the electric force on the sodium ion flowing into the cell is approximately 1.6 x 10^-12 N.