The electric field across a cellular membrane is 1.0x10^7 N/C directed into the cell. What is the magnitude of the electric forse on the sodium ion flowing into the cell? The charge on the sodium ion is +e.

User Icon for mrs. austin mrs. austin answered
14 years ago

q= elementary charge = e = 1.602x10^-19C

F=qE

F=(1.6x10^-19C)(1.0x10^7N/C)

F=1.6x10^-12 N

User Icon for drwls drwls answered
14 years ago

correct

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To find the magnitude of the electric force on the sodium ion flowing into the cell, we can use the formula:

Electric Force = Electric Field × Charge

Given:
Electric Field (E) = 1.0x10^7 N/C (directed into the cell)
Charge (q) = +e (charge on the sodium ion)

Substituting these values into the formula, we have:

Electric Force = (1.0x10^7 N/C) × (+e)

However, we need to convert the charge from elementary charge units to coulombs. The elementary charge (e) is approximately 1.6x10^(-19) coulombs.

So, the magnitude of the electric force on the sodium ion flowing into the cell can be calculated as:

Electric Force = (1.0x10^7 N/C) × (1.6x10^(-19) C)

Multiplying these values together, we get:

Electric Force = 1.6x10^(-12) N

Therefore, the magnitude of the electric force on the sodium ion flowing into the cell is 1.6x10^(-12) Newtons.

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the magnitude of the electric force on the sodium ion flowing into the cell, you can use the equation F = qE, where F is the electric force, q is the charge, and E is the electric field.

In this case, the electric field across the cellular membrane is given as 1.0x10^7 N/C directed into the cell, and the charge on the sodium ion is +e.

To get the magnitude of the electric force, we need to multiply the charge on the sodium ion by the electric field strength.

Given:
Electric field, E = 1.0x10^7 N/C
Charge on the sodium ion, q = +e

Now, we can substitute these values into the equation:

F = qE

F = (+e) * (1.0x10^7 N/C)

The numeric value of the elementary charge, e, is approximately 1.6 x 10^-19 C.

F = (1.6 x 10^-19 C) * (1.0x10^7 N/C)

Now, we can calculate the magnitude of the electric force:

F = 1.6 x 10^-19 C * 1.0x10^7 N/C

F = 1.6 x 10^-12 N

Therefore, the magnitude of the electric force on the sodium ion flowing into the cell is approximately 1.6 x 10^-12 N.