Asked by Liz

If the electric field near a proton is 9.00 x 10^-3 N/C, what is the distance from the proton?
Answered by Damon
E = 9*10^9 Q/r^2
here
Q = 1.6*10^-19
so
9*10^-3 = 9*10^9 (1.6*10^-19)/r^2

r^2 = 1.6 * 10^-7 = 16 * 10^-8

r = 4*10^-4 meters

= .4 millimeters
Answered by Liz
thanks!
Answered by Damon
You are welcome.
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