Asked by anonymous

A capacitor is constructed of two aluminum plate separated by a dielectric. the capacitance is measured to be 268.00 uf. without changing the dimensions of the plates, they are brought closer together so that the distance between the two plates is 1/2 of the original distance.
What is the new capacitance (in μF)?

Answers

Answered by Damon
Twice
see http://hyperphysics.phy-astr.gsu.edu/hbase/electric/pplate.html

same E, less distance
Answered by Damon
typo - excuse me, same V, less distance, so greater E
Answered by anonymous
@Damon, can you explain me what you wrote
Answered by anonymous
I don't understand
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