Question
A capacitor is constructed with two parallel metal plates each with an area of 0.61 m^2 and separated by d = 0.80 cm. The two plates are connected to a 5.0-volt battery. The current continues until a charge of magnitude Q accumulates on each of the oppositely charged plates. Find the charge Q.
Answers
I'm stuck, please help
the second question the above question is Find the capacitance of the parallel plates.
the second question the above question is Find the capacitance of the parallel plates.
I have to use this formula to find Q Q = CΔV, and C = (ε0*A)/d
These are what I did but don't know what ε0 is
C= (ε0*0.61 m^2 )/.0080m= stuck here. Is there anybody know what to do from here?
These are what I did but don't know what ε0 is
C= (ε0*0.61 m^2 )/.0080m= stuck here. Is there anybody know what to do from here?
ε0=8.85*10^-12
C=[(8.85*10^-12)*.61]/.008=
Q=([(8.85*10^-12)*.61]/.008=)*5=
Parallel Plate Capacitor Capacitance Calculator for second question
www.daycounter.com/Calculators/Plate-Capacitor-Calculator.phtml
C=[(8.85*10^-12)*.61]/.008=
Q=([(8.85*10^-12)*.61]/.008=)*5=
Parallel Plate Capacitor Capacitance Calculator for second question
www.daycounter.com/Calculators/Plate-Capacitor-Calculator.phtml