Asked by tina
Solve Algebraically:
5.((x+0)^2)/1+((y+.8)^2)/1=9
12. x^2=1.2y+4.8
i cant get the answer i keep doing it wrong someone please help
5.((x+0)^2)/1+((y+.8)^2)/1=9
12. x^2=1.2y+4.8
i cant get the answer i keep doing it wrong someone please help
Answers
Answered by
Reiny
first one:
((x+0)^2)/1+((y+.8)^2)/1=9
or
x^2 + (y+.8)^2 = 9
this is a circle with centre at (0, -.8) and radius 3
don't know what you meant by solve, there is nothing to solve for, you have
2 variables.
2nd one:
x^2=1.2y+4.8 ----> y = (5/6)x^2 - 4
parabola , see if you find the vertex and the focal point
((x+0)^2)/1+((y+.8)^2)/1=9
or
x^2 + (y+.8)^2 = 9
this is a circle with centre at (0, -.8) and radius 3
don't know what you meant by solve, there is nothing to solve for, you have
2 variables.
2nd one:
x^2=1.2y+4.8 ----> y = (5/6)x^2 - 4
parabola , see if you find the vertex and the focal point
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