Asked by Anonymous

Solve algebraically

x^2-6x+9>0
Answered by huy
<=>(x-3)^2>0 <=> -infinity<x<infinity
i applied a^2-2ab+b^2=(a-b)^2
Answered by Henry
x^2 - 6x + 9 > 0.
(x-3)^2 > 0,
Take sqrt of both sides:
x-3 > 0, X > 3.

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