Asked by Russell
                Solve algebraically using one variable: Find three consecutive odd integers such that the
product of the first integer and the third integer is equal to nine more than twelve times the middle integer.
            
        product of the first integer and the third integer is equal to nine more than twelve times the middle integer.
Answers
                    Answered by
            PsyDAG
            
    Let the first integer be x-2, then middle integer is x and the third is x+2.
(x-2)(x+2) = 12x + 9
X^2 - 4 = 12x + 9
x^2 - 12x - 13 = 0
(x+1)(x-13) = 0
11 * 15 = 12*13 + 9
    
(x-2)(x+2) = 12x + 9
X^2 - 4 = 12x + 9
x^2 - 12x - 13 = 0
(x+1)(x-13) = 0
11 * 15 = 12*13 + 9
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