Asked by Russell

Solve algebraically using one variable: Find three consecutive odd integers such that the
product of the first integer and the third integer is equal to nine more than twelve times the middle integer.

Answers

Answered by PsyDAG
Let the first integer be x-2, then middle integer is x and the third is x+2.

(x-2)(x+2) = 12x + 9

X^2 - 4 = 12x + 9

x^2 - 12x - 13 = 0

(x+1)(x-13) = 0

11 * 15 = 12*13 + 9

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