Asked by Russell
Solve algebraically using one variable: Find three consecutive odd integers such that the
product of the first integer and the third integer is equal to nine more than twelve times the middle integer.
product of the first integer and the third integer is equal to nine more than twelve times the middle integer.
Answers
Answered by
PsyDAG
Let the first integer be x-2, then middle integer is x and the third is x+2.
(x-2)(x+2) = 12x + 9
X^2 - 4 = 12x + 9
x^2 - 12x - 13 = 0
(x+1)(x-13) = 0
11 * 15 = 12*13 + 9
(x-2)(x+2) = 12x + 9
X^2 - 4 = 12x + 9
x^2 - 12x - 13 = 0
(x+1)(x-13) = 0
11 * 15 = 12*13 + 9
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