Question

Solve csc^2 x = 5 algebraically over the interval 0 <= x <= 2pi. Round to the nearest hundredth.

My answer: csc x = sqrt 5

= 2.24

Answer 1

can't csc x= -sqrt5 also?

and, you haven't solve for the x values yet..

Answer 2

Then x = arccsc sqrt 5
= 0.46

x = arccsc -sqrt 5, which is -arcsc sqrt 5, or -0.46.