Asked by Anonymous
Solve csc^2 x = 5 algebraically over the interval 0 <= x <= 2pi. Round to the nearest hundredth.
My answer: csc x = sqrt 5
= 2.24
My answer: csc x = sqrt 5
= 2.24
Answers
Answered by
bobpursley
can't csc x= -sqrt5 also?
and, you haven't solve for the x values yet..
and, you haven't solve for the x values yet..
Answered by
Anonymous
Then x = arccsc sqrt 5
= 0.46
x = arccsc -sqrt 5, which is -arcsc sqrt 5, or -0.46.
= 0.46
x = arccsc -sqrt 5, which is -arcsc sqrt 5, or -0.46.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.