Asked by Anonymous

Solve csc^2 x = 5 algebraically over the interval 0 <= x <= 2pi. Round to the nearest hundredth.

My answer: csc x = sqrt 5

= 2.24

Answers

Answered by bobpursley
can't csc x= -sqrt5 also?

and, you haven't solve for the x values yet..
Answered by Anonymous
Then x = arccsc sqrt 5
= 0.46

x = arccsc -sqrt 5, which is -arcsc sqrt 5, or -0.46.
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