Asked by Sarah
Could someone help me calculate the integral:
a = 0 b = pi^(-3/2)
x*sin(x^3)dx
a = 0 b = pi^(-3/2)
x*sin(x^3)dx
Answers
Answered by
oobleck
This one cannot be done using elementary functions. You will have to use some numerical method.
Now, if you had said x^2 sin(x^3) dx then that would just have been sin(u) du, which is easy.
Now, if you had said x^2 sin(x^3) dx then that would just have been sin(u) du, which is easy.
Answered by
Damon
I bet it was indeed x^2 sin(x^3) dx
Answered by
oobleck
yeah, and I don't like that 1/√π<sup><sup>3</sup></sup> as a limit, either
More like ∛(π/2)
More like ∛(π/2)
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