Asked by holly
Calculate ΔG° (in kJ/mol) for the following reaction at 1 atm and 25 °C:
C2H6 (g) + O2 (g) → CO2 (g) + H2O (l) (unbalanced)
ΔGf° C2H6 (g) = –32.89 kJ/mol; ΔGf° CO2 (g) = –394.4 kJ/mol; ΔGf° H2O (l) = –237.13 kJ/mol
C2H6 (g) + O2 (g) → CO2 (g) + H2O (l) (unbalanced)
ΔGf° C2H6 (g) = –32.89 kJ/mol; ΔGf° CO2 (g) = –394.4 kJ/mol; ΔGf° H2O (l) = –237.13 kJ/mol
Answers
Answered by
bobpursley
You need to study Hess'law.
balance the equation first.
2C2H6 (g) + 7O2 (g) → 4CO2 (g) + 6H2O (l)
free energy=3(HfCO2)+6Hf(H20)-2HfC2H6)
balance the equation first.
2C2H6 (g) + 7O2 (g) → 4CO2 (g) + 6H2O (l)
free energy=3(HfCO2)+6Hf(H20)-2HfC2H6)
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