Asked by kathy
calculate the pH of a 1.25 x 10^-3 M HNO3 solution
Answers
Answered by
DrBob222
This is hardly organic chemistry.
(HNO3) = 1.25E-3M.
Since HNO3 is a strong acid (100% ionized), that means (HNO3) = (H^+); therefore, (H^+) = 1.25E-3 and
pH = -log(H^+) = -log(1.25E-3) = ?? The answer is approximately 3
(HNO3) = 1.25E-3M.
Since HNO3 is a strong acid (100% ionized), that means (HNO3) = (H^+); therefore, (H^+) = 1.25E-3 and
pH = -log(H^+) = -log(1.25E-3) = ?? The answer is approximately 3
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