Asked by logan
What two positive consecutive integers have a product of 72?
Answers
Answered by
Bosnian
a = first mumber
b = second number
b = a + 1
a ∙ b = 72
a ∙ ( a + 1 ) = 72
a² + a = 72
a² + a - 72 = 0
The solutions are:
a = - 9 and 8
For a = - 9
b = a + 1 = - 9 + 1 = - 8
For a = 8
b = a + 1 = 8 + 1 = 9
The solutions are:
a = - 9 , b = - 8
and
a = 8 , b = 9
( - 9 ) ∙ ( - 8 ) = 72
8 ∙ 9 = 72
b = second number
b = a + 1
a ∙ b = 72
a ∙ ( a + 1 ) = 72
a² + a = 72
a² + a - 72 = 0
The solutions are:
a = - 9 and 8
For a = - 9
b = a + 1 = - 9 + 1 = - 8
For a = 8
b = a + 1 = 8 + 1 = 9
The solutions are:
a = - 9 , b = - 8
and
a = 8 , b = 9
( - 9 ) ∙ ( - 8 ) = 72
8 ∙ 9 = 72
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