Asked by Alex
It takes Earth 365 days to complete one orbit around our sun. Knowing that the magnitude of the average acceleration the Earth experiences over half an orbit is 3.78 x 10^-3 m/s^2, what is the average speed with which it travels? Express your answer in m/s.
Answers
Answered by
Damon
a = v^2/R = 3.78 *10^-3
2 pi R = v T = v (365d * 24 h/d * 3600 s/h)
R = 5.02*10^6 seconds * v
3.78*10^-3 = v^2 / (5.02*10^6 v)
v = 3.78 * 5.02 * 10^3 = 18,976 meters/second
2 pi R = v T = v (365d * 24 h/d * 3600 s/h)
R = 5.02*10^6 seconds * v
3.78*10^-3 = v^2 / (5.02*10^6 v)
v = 3.78 * 5.02 * 10^3 = 18,976 meters/second
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