Asked by Kelly
If it takes 45 days for 80.0 mg of a particular radioactive isotope to decay to 10.0 mg what is its half-life?
Answers
Answered by
Steve
80(1/2)^t = 10
(1/2)^t = 1/8
t = 3
so, 45 days is 3 half-lives
(1/2)^t = 1/8
t = 3
so, 45 days is 3 half-lives
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.