Question
If it takes 45 days for 80.0 mg of a particular radioactive isotope to decay to 10.0 mg what is its half-life?
Answers
Steve
80(1/2)^t = 10
(1/2)^t = 1/8
t = 3
so, 45 days is 3 half-lives
(1/2)^t = 1/8
t = 3
so, 45 days is 3 half-lives