Asked by A
Find the area of the region enclosed by the inner loop of the curve.
r = 4 + 8 sin(θ)
r = 4 + 8 sin(θ)
Answers
Answered by
Steve
r=0 at θ=7π/6, 11π/6
So, using symmetry, the area is
a = 2∫[7π/6,3π/2] 1/2 (4+8sinθ)^2 dθ = 8(2π-3√3) ≈ 8.6963
So, using symmetry, the area is
a = 2∫[7π/6,3π/2] 1/2 (4+8sinθ)^2 dθ = 8(2π-3√3) ≈ 8.6963
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