Ask a New Question

Asked by A

Find the area of the region enclosed by the inner loop of the curve.
r = 4 + 8 sin(θ)
7 years ago

Answers

Answered by Steve
r=0 at θ=7π/6, 11π/6
So, using symmetry, the area is

a = 2∫[7π/6,3π/2] 1/2 (4+8sinθ)^2 dθ = 8(2π-3√3) ≈ 8.6963
7 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

1) Find the area of the region bounded by the curves y=arcsin (x/4), y = 0, and x = 4 obtained by in... Find the area of the region in the first quadrant bounded by the curves y=sin(x)cos^2(x),... Find the area of the region bounded by the curve y=x^2*e^x and the x-axis, 0≤x≤1 Find the area of the region enclosed between the curves y=(x-2)^4 and y=(x-2)^3. Find the area of the region that is inside the graph of r = 1 and outside of the graph of r = 1 + co... Find the area of the region that is common to the graphs of r = 3 + 2 sin θ and r = 2. (15 points)... Find the area of the region that lies within thecurve r=2cosθ but is outside the curve r=1.To get fu... Find the area of the region bounded by y = x^2 + 2x -6 and y = 3x. Find the area of region between the graph of y=x^2+4x+3 and y=x^2 between the intervals x=1 and x=3
Submit Your Answer

Question

Find the area of the region enclosed by the inner loop of the curve.
r = 4 + 8 sin(θ)

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use