Asked by Matt
Find the area of the region in the first quadrant bounded by the curves y=sin(x)cos^2(x), y= 2xcos(x^2), and y=4-4x
a. 1.8467
b. 0.16165
c. 0.36974
d. 1.7281
e. 0.37859
a. 1.8467
b. 0.16165
c. 0.36974
d. 1.7281
e. 0.37859
Answers
Answered by
oobleck
?? The graphs intersect at 5 points on the interval [0,π/2]
I'm having a hard time deciding how to divide it up. I've tried three ways, and I get none of the choices.
What have you done so far? Maybe I'm out in left field.
I'm having a hard time deciding how to divide it up. I've tried three ways, and I get none of the choices.
What have you done so far? Maybe I'm out in left field.
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