Ask a New Question

Question

Find the area of the region in the first quadrant bounded by the curves y=sin(x)cos^2(x), y= 2xcos(x^2), and y=4-4x

a. 1.8467
b. 0.16165
c. 0.36974
d. 1.7281
e. 0.37859
6 years ago

Answers

oobleck
?? The graphs intersect at 5 points on the interval [0,π/2]
I'm having a hard time deciding how to divide it up. I've tried three ways, and I get none of the choices.

What have you done so far? Maybe I'm out in left field.
6 years ago

Related Questions

Find the area of the region bounded by the graphs of y = x2 − 4x and y = x − 4. a) - 4.500 b)... Find the area of the region bounded by the functions f(x) = x^4 and g(x) = |x|. a) 1.3 b) 5.2 c... Find the área of the región bounded by the graphs of y=x, y=-x+4, and y=0 A) 4 B) 2 C) 8 D) no... Find the area of the region bounded by the graphs of y = −x2 + 3x + 4 and y = 4. a) 2.7 b) 4.5... Find the area of the region bounded by the curves y = sin x, y = csc^2x, x = pi/4, and x = (3pi)/4. Find the area of the region that lies outside the circle x^2 + y^2 = 4 but inside the circle x^2 +... Find the area of the region bounded by the graphs of the equations y=cos^2(x), y=sin^2(x), x=-pi/4,... Find the area of the region bounded by the curve y = f(x) = (x^3)-4x+1 and the tangent line to the c... Find the area of the region enclosed between and from to . Hint: Notice that this region consists...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use