The curves intersect at θ = 7π/6, 11π/6
symmetry allows us to say that
a = 2∫[3π/2,11π/6] 1/2 (2^2 - (3+2sinθ)^2) dθ
= 11√3/2 - 7π/3 = 2.196
Find the area of the region that is common to the graphs of r = 3 + 2 sin θ and r = 2. (15 points)
A) 2.196
B) 10.370
C) 24.187
D) None of these
1 answer