Ask a New Question

Question

Find the area of the region that lies within thecurve r=2cosθ but is outside the curve r=1.To get full credit you need to SHOW WORK.
4 years ago

Answers

oobleck
I don't need full credit, but you can supply any steps you think necessary.
since the region is symmetric, just double the area in the first quadrant,
The two circles intersect where
2cosθ = 1
θ = π/3
so the area is
A = 2∫[0,π/3] 1/2 (R^2-r^2) dθ
= 2∫[0,π/3] 1/2 ((2cosθ)^2-1^2) dθ = 2(π/6 + √3/4)
4 years ago

Related Questions

Find the area of the region bounded by the graphs of y = x2 − 4x and y = x − 4. a) - 4.500 b)... Find the area of the region bounded by the functions f(x) = x^4 and g(x) = |x|. a) 1.3 b) 5.2 c... Find the área of the región bounded by the graphs of y=x, y=-x+4, and y=0 A) 4 B) 2 C) 8 D) no... Find the area of the region bounded by the graphs of y = −x2 + 3x + 4 and y = 4. a) 2.7 b) 4.5... Find the area of the region bounded by the curves y = sin x, y = csc^2x, x = pi/4, and x = (3pi)/4. Find the area of the region that lies outside the circle x^2 + y^2 = 4 but inside the circle x^2 +... Find the area of the region bounded by the graphs of the equations y=cos^2(x), y=sin^2(x), x=-pi/4,... Find the area of the region bounded by the curve y = f(x) = (x^3)-4x+1 and the tangent line to the c... Find the area of the region enclosed between and from to . Hint: Notice that this region consists...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use