Asked by Anonymous
Find the area of this region in the coordinate plane that satisfies both the inequalities x^2 + y^2 ≤ 8 and y ≥ |x|
Answers
Answered by
oobleck
since y = |x| subtends an angle of 90° at the center of the circle, the area in question is 1/4 of a circle of radius r^2 = 8
so, that would be 1/4 (8π) = 2π
so, that would be 1/4 (8π) = 2π
Answered by
Anonymous
Does quadrant 2 not also qualify? I think 180 degrees
Answered by
Anonymous
sorry, 45deg in each upper quadrant, oobleck is correct
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