Asked by Anonymous
Find the area of the region bounded by the curve ๐ฆ =square root of x^9-9/x^2,
๐กโ๐ ๐ฅ โ ๐๐ฅ๐๐ , ๐๐๐ ๐กโ๐ ๐๐๐๐ ๐ฅ = 5
๐กโ๐ ๐ฅ โ ๐๐ฅ๐๐ , ๐๐๐ ๐กโ๐ ๐๐๐๐ ๐ฅ = 5
Answers
Answered by
oobleck
Do you mean
โ(x^9-9) / x^2
or
โ((x^9-9)/x^2)
or, more probably,
โ(x^2-9) / x^2
??
In any case, you have problems at x=0
โ(x^9-9) / x^2
or
โ((x^9-9)/x^2)
or, more probably,
โ(x^2-9) / x^2
??
In any case, you have problems at x=0
Answered by
Anonymous
hello, correction, its โ(x^2-9) / x^2
Answered by
oobleck
since y is undefined for x<3 you have a problem. But, using integration by parts,
โซโ(x^2-9) / x^2 dx = -arcsin(x/3) - โ(x^2-9)/x
now it's even worse. arcsin(x/3) is undefined for x>3 !
Maybe you can figure out what's to be done ...
โซโ(x^2-9) / x^2 dx = -arcsin(x/3) - โ(x^2-9)/x
now it's even worse. arcsin(x/3) is undefined for x>3 !
Maybe you can figure out what's to be done ...
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