Question

Find the area of the region bounded by the curve 𝑦 =square root of x^9-9/x^2,
π‘‘β„Žπ‘’ π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠, π‘Žπ‘›π‘‘ π‘‘β„Žπ‘’ 𝑙𝑖𝑛𝑒 π‘₯ = 5

Answers

oobleck
Do you mean
√(x^9-9) / x^2
or
√((x^9-9)/x^2)
or, more probably,
√(x^2-9) / x^2

??
In any case, you have problems at x=0
Anonymous
hello, correction, its √(x^2-9) / x^2
oobleck
since y is undefined for x<3 you have a problem. But, using integration by parts,

∫√(x^2-9) / x^2 dx = -arcsin(x/3) - √(x^2-9)/x

now it's even worse. arcsin(x/3) is undefined for x>3 !

Maybe you can figure out what's to be done ...

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