Question
Find the area of the region bounded by the curve π¦ =square root of x^9-9/x^2,
π‘βπ π₯ β ππ₯ππ , πππ π‘βπ ππππ π₯ = 5
π‘βπ π₯ β ππ₯ππ , πππ π‘βπ ππππ π₯ = 5
Answers
oobleck
Do you mean
β(x^9-9) / x^2
or
β((x^9-9)/x^2)
or, more probably,
β(x^2-9) / x^2
??
In any case, you have problems at x=0
β(x^9-9) / x^2
or
β((x^9-9)/x^2)
or, more probably,
β(x^2-9) / x^2
??
In any case, you have problems at x=0
Anonymous
hello, correction, its β(x^2-9) / x^2
oobleck
since y is undefined for x<3 you have a problem. But, using integration by parts,
β«β(x^2-9) / x^2 dx = -arcsin(x/3) - β(x^2-9)/x
now it's even worse. arcsin(x/3) is undefined for x>3 !
Maybe you can figure out what's to be done ...
β«β(x^2-9) / x^2 dx = -arcsin(x/3) - β(x^2-9)/x
now it's even worse. arcsin(x/3) is undefined for x>3 !
Maybe you can figure out what's to be done ...