Find the area of the region bounded by the curve ๐‘ฆ =square root of x^9-9/x^2,

๐‘กโ„Ž๐‘’ ๐‘ฅ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘ , ๐‘Ž๐‘›๐‘‘ ๐‘กโ„Ž๐‘’ ๐‘™๐‘–๐‘›๐‘’ ๐‘ฅ = 5

3 answers

Do you mean
โˆš(x^9-9) / x^2
or
โˆš((x^9-9)/x^2)
or, more probably,
โˆš(x^2-9) / x^2

??
In any case, you have problems at x=0
hello, correction, its โˆš(x^2-9) / x^2
since y is undefined for x<3 you have a problem. But, using integration by parts,

โˆซโˆš(x^2-9) / x^2 dx = -arcsin(x/3) - โˆš(x^2-9)/x

now it's even worse. arcsin(x/3) is undefined for x>3 !

Maybe you can figure out what's to be done ...