Question

A balloon is inflated to a volume of 7.0 L on a day when the atmospheric pressure is 765 mmHg. The next day, as a storm front arrives, the atmospheric pressure drops to 725 mmHg. Assuming the temperature remains constant, what is the new volume of the balloon, in liters?
the volume is inversely proportional to the ambient pressure

v = 7.0 L * (765 / 725)

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